Standard solutions, primary standards and choosing an indicator
What a standard solution is
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A standard solution is a solution whose concentration is known accurately.
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Everything in your calculation is measured against it, so an error in its concentration is an error in your final answer, by the same percentage.
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This is why the Merit criteria name it explicitly: you must accurately determine the concentration of the standard solution, not read it off a bottle.
Primary standards
A primary standard is a substance pure and stable enough that you can make a standard solution simply by weighing it out. To qualify, a substance must be:
- Available in high purity, so the mass weighed really is the substance.
- Stable in air — not absorbing water or carbon dioxide, and not decomposing.
- Of high molar mass, so weighing errors are a small percentage of the mass.
- Soluble in water.
| Substance | Primary standard? | Why |
|---|---|---|
| Anhydrous sodium carbonate, Na2CO3 | Yes | pure, stable when dried, M = 106 g mol−1 |
| Potassium hydrogen phthalate (KHP) | Yes | very pure, stable, M = 204 g mol−1 |
| Oxalic acid dihydrate | Yes | stable, known water of crystallisation |
| Sodium hydroxide, NaOH | No | absorbs water and CO2 from the air |
| Hydrochloric acid | No | a solution; concentration changes as HCl evaporates |
| Potassium permanganate | No | slowly decomposes; oxidises traces of organic matter |
- If your titrant is not a primary standard, it must be standardised — titrated against a solution made from one that is.
Making a standard solution from a primary standard
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Calculate the mass needed for the concentration and volume you want.
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Weigh it accurately on a 4-figure balance, recording the actual mass, not the target mass.
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Dissolve it completely in a beaker with a small amount of distilled water.
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Transfer to a volumetric flask, rinsing the beaker and stirring rod into the flask.
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Make up to the mark, then invert to mix at least ten times.
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Use the actual mass weighed in the calculation. Trying to hit an exact target mass wastes time and gains nothing — any mass near the target works, as long as you record it accurately.
Standardising a titrant
- Standardising means finding the true concentration of a solution by titrating it against a primary standard.
- For example, sodium hydroxide of roughly 0.1 mol L−1 is titrated against a standard solution of sodium carbonate made by weighing:
- Note this reaction's 2 : 1 ratio, which is one reason sodium carbonate is such a convenient primary standard for this standard's non-1:1 requirement.
Choosing an indicator
- An indicator changes colour over a narrow pH range. The right one changes colour at the pH of the equivalence point of your titration.
| Titration | pH at equivalence | Indicator | Colour change |
|---|---|---|---|
| Strong acid + strong base | 7 | phenolphthalein or methyl orange | — |
| Weak acid + strong base (e.g. vinegar + NaOH) | above 7 | phenolphthalein | colourless → faint pink |
| Strong acid + weak base (e.g. HCl + ammonia) | below 7 | methyl orange | yellow → orange/red |
| Weak acid + weak base | — | none suitable | do not attempt — no sharp pH jump |
- Phenolphthalein changes over about pH 8.3–10; methyl orange over about pH 3.1–4.4.
- The reason a weak acid titration needs phenolphthalein is that the salt formed is basic, so the equivalence point sits above pH 7 and methyl orange would change colour far too early.
Self-indicating titrations
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Some redox titrations need no indicator at all, because a reagent changes colour itself.
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Potassium permanganate is the classic: it is purple, and its product Mn2+ is colourless, so the endpoint is the first permanent faint pink from the first drop of unreacted MnO4−.
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Iodine titrations use starch, added near the endpoint, giving a sharp blue-black to colourless change.
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Self-indicating titrations are a good choice for coloured products, since there is no indicator colour to be masked.
Worked ExampleMaking up a standard solution
A student needs 250.0 mL of a sodium carbonate standard solution with a concentration of approximately 0.100 mol L−1. Calculate the mass required, then determine the exact concentration if the mass actually weighed was 2.6738 g. (M(Na2CO3) = 105.99 g mol−1)
Step 1 — Find the moles needed
Note the volume was converted from mL to L before use — 250.0 mL is 0.2500 L.
Step 2 — Convert moles to a mass
So the student should weigh out approximately 2.65 g.
Step 3 — Use the mass actually weighed
The student weighed 2.6738 g, which is close to the target but not identical — and that is completely fine. What matters is that the mass is known accurately, not that it hits a round number.
Step 4 — Calculate the exact concentration
Step 5 — Choose the significant figures
The mass was measured to 5 significant figures and the volume of the volumetric flask to 4, so the concentration is limited by the volume: 4 significant figures is appropriate.
Answer: about 2.65 g is required; the solution actually made was 0.1009 mol L−1.